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Sabtu, 11 April 2009

contoh soal keseimbangan


Dik : W = 90 N
α1 = 10 o
α2 = 5o
Dit : T1 & T2

Jawab
T1X = T1 COS 10
= T1 (0.98)
T2X = T2 COS 5
= T2 (0.99)
T1Y = T2 Sin 5
= T2 (0.17)
T2Y = T2 Sin 5
= T2 (0.09)

Syarat :
FX = 0
T2X – T1X = 0
0.99 T2 – 0.98 T1 = 0
0.99 T2 = 0.98 T1

FY = 0
T1Y + T2Y – W = 0
TIY + T2Y = 0
0.17 T1Y + 0.09T2Y = 90

Sub. Persamaan 1 & 2
-0.98 T1 + 0.99 T2 = 0 x 17
0.17 T1 + 0.09 T2 = 90 x 98

-16.66 T1 + 16.83 T2 = 0
16.66 T1 + 8.82 T2 = 8820
25.65T2 = 8820
T2 = 343.8 N
-0.98 T1 + 0.99 T2 = 0
-0.98 T1 + 0.99 (343.8) = 0
-0.98 T1 =-340.36
T1 =347.3 N
posted by Kelompok Fisika at 21.36

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